10 Jan 2016

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Unsolved Problems on Trigonometry Functions

UNSOLVED PROBLEMS ON TRIGONOMETRY FUNCTIONS:


  1. Find value of Cos2a+(1/1+cot2a)

    1. 0

    2. 1

    3. 2

    4. 3



  2. Find value of 2sin2a+4sec2a+5cot2a+2cos2a-4tan2a-5cosec2a

    1. 0

    2. 1

    3. 2

    4. 3



  3. Find the value of (cosA-sinA)2+(cosA+sinA)2

    1. 0

    2. 1

    3. 2

    4. 3



  4. Find the value of Cot2A x (sec2A-1)

    1. 0

    2. 1

    3. 2

    4. 3



  5. Find the value of (secA x cotA)2 – (cosec A x cosA)2

    1. 0

    2. 1

    3. 2

    4. 3



  6. secA/(cotA+tanA) will be equal to

    1. cosA

    2. cosecA

    3. sinA

    4. tanA



  7. (1+tanA+secA)(1+cotA-cosecA) will be equal to

    1. 0

    2. 1

    3. 2

    4. 3



  8. Cos6A+sin6A=

    1. 1-3(cosA x sinA)2

    2. 1+3(cosA x sinA)2

    3. 1-3(cosA x sinA)3

    4. 1-3(cosA x sinA)6



  9. (sin2A x cos2B) – (cos2A x sin2B) will be equal to

    1. Sin2A-cos2A

    2. Sin2A+cos2A

    3. Cos2A – cos2A

    4. Sin2A-Sin2B



  10. (tanA+cotA)(secA-cosA)(cosecA-sinA)=

    1. 0

    2. 1

    3. 2

    4. 3





  1. If Tan2A+Tan4A=1 then what is the value of cos2A+cos4A, given that A is an acute angle?

    1. 0

    2. 1

    3. 2

    4. 3



  2. (cosecA-cotA)2=

    1. (1-cosA)/(2+cosA)

    2. (1+cosA)/(1-cosA)

    3. (1-cosA)/(1+cosA)

    4. (1-cosA)x(1+cosA)



  3. [(tanA+secA)2-1]/[(tanA+secA)2+1], will be equal to

    1. tanA

    2. secA

    3. sinA

    4. cosA



  4. [(sin220+sin270)/(sec250-cos240)]+2cosec258-2(cot58xtan32)-(4tan13 x tan37 x tan45 x tan53 x tan77)

    1. 0

    2. -1

    3. 1

    4. None of above



  5. If cotA=root 7, what is the value of (cosec2A-sec2A)/( cosec2A+sec2A)

    1. 3/2

    2. 3/4

    3. 4/3

    4. 2/3



  6. (sinA+cosecA)2+(cosA+secA)2 will be equal to

    1. Tan2A+cot2A+4

    2. Tan2A-cot2A+5

    3. Tan2A-cot2A

    4. Tan2A+cot2A+7




ANSWERS:
1)b, 2)b, 3)c, 4)b, 5)b, 6)c , 7)c, 8)a, 9)d, 10)b, 11)b, 12)c,13)d, 14)b, 15)b, 16)d

LINKS

|| Basics Of Trigonometry||

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